Acceleration of a 1kg Mass Under a 100N Force

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When a 100N force acts on a 1kg mass, the acceleration is calculated using F=ma, resulting in an acceleration of 100 meters per second squared. However, applying this principle to buoyancy, particularly for bubbles, complicates the situation, as it can lead to unrealistic predictions of unlimited acceleration. The discussion highlights the need for a more nuanced understanding of forces in fluid dynamics, suggesting Stokes' Equations as a better framework for analyzing terminal velocity in falling spheres. The conversation emphasizes that not all scenarios can be simplified to basic physics equations due to the influence of nonconservative forces. Overall, the complexities of real-world physics require careful consideration beyond straightforward applications of F=ma.
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obvious question, but what happens when a 100N force acts on a mass of 1kg. What is the acceleration? is it 100 meters per second squared?
 
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Obvious answer. F=ma.
 
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see "followup to easy question"
 
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I was looking online and i finally found where everything goes wrong.. With buoyancy, you cannot use simply F=ma to calculate acceleration of a bubble. It is not that simple. it ends up giving nearly unlimited acceleration in many circumstances when trying to apply it. ill get back about it when i have timelooren try not to be so cocky next time. everything is not always as straightforward as it may seem
 
Sorry.

I still maintain that F=ma. In your other thread, one post suggests "Check out Stokes' Equations on the terminal velocity of falling spheres." This seems the best approach. There, simply put, F=bv, where b is a damping constant. I believe that the velocity dependence arises not directly from a fundamental law but from nonconservative (e. g., frictional) action by forces on the atomic level.
 

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