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During a serve, a tennis racket of mass 1.6 kg is given an angular acceleration of 157 rad/sec2. At the top of the serve, the racket has an angular speed of 13 rad/sec.

If the distance between the top of the racket and the shoulder is 1.4 m,

**what is the total acceleration of the top of the racket?**

atotal = ? m/sec2

Okay so I'm having some trouble here. I know that a

*total*is the combination of

*atranslational*and a

*centripetal*, well rather the addition of the squares of each equal to the square of a

*total*, but I'm not sure how to solve for atranslational.

I know that a

*cp*= rw^2 and I solved using the values given to get 118.3m/s^2.

However, when it comes to solving a

*t*= ra I don't know how to get the angular acceleration. I'm pretty sure the initial angular acceleration isn't what you use, as I got the wrong answer, but how else do I determine it at the top?

Any help would be appriciated :)