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During a serve, a tennis racket of mass 1.6 kg is given an angular acceleration of 157 rad/sec2. At the top of the serve, the racket has an angular speed of 13 rad/sec.

If the distance between the top of the racket and the shoulder is 1.4 m,what is the total acceleration of the top of the racket?

atotal = ? m/sec2

Okay so I'm having some trouble here. I know that atotalis the combination ofatranslationaland acentripetal, well rather the addition of the squares of each equal to the square of atotal, but I'm not sure how to solve for atranslational.

I know that acp= rw^2 and I solved using the values given to get 118.3m/s^2.

However, when it comes to solving at= ra I don't know how to get the angular acceleration. I'm pretty sure the initial angular acceleration isn't what you use, as I got the wrong answer, but how else do I determine it at the top?

Any help would be appriciated :)

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# Homework Help: Acceleration Of Tennis Racket (Linear And Rotational Quantites)

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