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Acceleration of the elevator

  1. Oct 3, 2008 #1

    Abb

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    1. The problem statement, all variables and given/known data

    While an elevator of mass 2442 kg moves upward, the tension in the cable is 34.2 kN

    2. Relevant equations

    (a) What is the ?
    (a) What is the acceleration of the elevator?
    3. The attempt at a solution
    a= f/m
    a= 34200N/2442kg =14.0
     
  2. jcsd
  3. Oct 3, 2008 #2
    Why is this posted twice?

    relevant equations: what is the ?
    what is the acceleration of the elevator?

    what does this mean?

    If you just want to solve for acceleration, First sum up all of the forces.

    You have the motor pulling the elevator up, and gravity pulling it down.
    The net force = 34.2 KN,
    The force on account of gravity = ma = 2442 * 9.81 = 23956N
    Therefore, the force pulling up = 34200 - 23956
    You can solve it from here.
     
  4. Oct 3, 2008 #3

    Abb

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    Thank. and sorry i thought firs time it didnt go through
     
  5. Oct 3, 2008 #4

    tiny-tim

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    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi Abb! Welcome to PF! :smile:
    Yup, that happens sometimes :redface:

    depends on what mood the server is in … :biggrin:
     
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