GregAshmore said:
This is my problem: The muon isn't passing any clocks. It is at rest in its frame, watching the world go by.
Sure, and the two clocks in the lab frame pass it in succession. I didn't mean "pass it" to suggest anything about which was moving, I just meant that there was a moment the muon clock and the first lab clock passed one another, and then another moment the muon clock and the second lab clock passed one another. Even if you analyze things from the perspective of the muon frame where these two clocks are running slow, if you take into account that they are also out-of-sync in the muon frame, you still end up with the prediction that the difference in readings between the two lab clocks at the moment they pass the muon is greater than 4.5 microseconds.
GregAshmore said:
If the problem were posed in the usual manner, as a resting observer measuring the elapsed time as an object moves between two positions, and the task was to calculate the elapsed time in the frame of the moving object, the answer would be smaller than the time measured in the rest frame.
No, all frames always agree about all
local measurements, specifically what any two clocks read at the moment they pass next to one another. If you have a pair of clocks A and B at rest and synchronized in the lab frame and a pair of clocks A' and B' at rest and synchronized in the muon frame, then the two lab clocks can be used to measure the time elapsed
in the lab frame on a single muon clock, and likewise the two muon clocks can be used to measure the time elapsed
in the muon frame on a single lab clock. All frames will agree on local facts like what times A and A' showed at the moment they passed one another, and the result will be that the lab clock is measured to run slow in the muon frame and the muon clock is measured to run slow in the lab frame.
Let's pick an example with easier-to-deal with numbers. Say we have a pair of clocks A' and B' on a rocket which is moving at 0.8c relative to the lab frame, and the clocks are 20 light-seconds apart in the rocket rest frame, meaning they are 12 light-seconds apart in the lab frame due to length contraction. Also these two clocks are synchronized in the rocket's own frame, which means the rear clock is running ahead of the front clock by 0.8*20 = 16 seconds in the lab frame (relativity of simultaneity). Meanwhile we also have two clocks A and B at rest in the lab frame, and 20 light-seconds apart in the lab frame, and synchronized in the lab frame. Suppose before any of them pass one another, they are arranged like the "diagram" below, with B' to the left of A' and A' to the left of A and A to the left of B, and with B' and A' traveling to the right:
B'...A'---> A...B
So, first A' will pass A, and let's suppose A reads t=0 and A' reads t'=0 at that moment. So at t=0 in the lab frame, B' is 12 light-seconds away from A and it reads t'=16 seconds. Moving at 0.8c, it takes 12/0.8 = 15 seconds in the lab frame to reach A, so A reads t=15 when B' passes it, but B' has only elapsed 0.6*15 = 9 seconds in that time, so since it started reading t'=16 it will read t'=16+9=25 at the moment it passes A.
So, so far we have these local facts:
*When A and A' pass, A reads t=0 and A' reads t'=0
*When A and B' pass, A reads t=15 and B' reads t'=25
Now since A and B are 20 light-seconds apart in the lab frame, and A' passed A at t=0 and is moving at 0.8c, A' will pass B at t=20/0.8=25 seconds in the lab frame. At this moment B reads t=25 and since A' read t'=0 when it passed A and is running slow by a factor of 0.6, when A' passes B, A' reads t'=25*0.6=15 seconds.
Likewise since B' passed A at t=15 in the lab frame, B' will pass B 25 seconds later in the lab frame, when B reads t=15+25=40 seconds. B' will tick forward by 25*0.6=15 seconds in this time, but since B' already read t'=25 seconds at the moment it passed A, that means B' will read t'=25+15=40 seconds when it passes B.
So, we have the following local facts:
*When B and A' pass, B reads t=25 and A' reads t'=15
*When B and B' pass, B reads t=40 and B' reads t'=40
So, the full listing of local facts about all 4 passing events is:
1. When A and A' pass, A reads t=0 and A' reads t'=0
2. When A and B' pass, A reads t=15 and B' reads t'=25
3. When B and A' pass, B reads t=25 and A' reads t'=15
4. When B and B' pass, B reads t=40 and B' reads t'=40
Both frames agree about these local facts (that's a basic principle of relativity, there is always complete agreement about local facts like this). But notice that if
either frame uses a pair of their own clocks to measure the time elapsed on one of the other frame's clocks, they conclude the other frame's clock is running slow! For example, in the lab frame, if we look at local events 1 and 3, we find that the rocket clock A' elapsed 15 seconds in the time between passing lab clock A and passing lab clock B, while A read t=0 as A' passed it and B read t=25 as A' passed it, meaning that in the lab frame it took 25 seconds for A' to tick forward by 15 seconds. But in the rocket frame, if we look at local events 1 and 2, we find that the lab clock A elapsed 15 seconds in the time between passing rocket clock A' and passing rocket clock B', while A' read t'=0 as A passed it and B' read t'=25 as A passed it, meaning that in the rocket frame it took 25 seconds for A to tick forward by 15 seconds. The situation is entirely symmetrical, as you can see by the numbers in the four local passing events!
For a more visual illustration of the symmetry between frames, you might follow the suggestion I made on your
other thread:
You might find it helpful to take a look at the illustrations I did for
this thread showing two rulers moving at relativistic speeds relative to one another, each with clocks placed at each ruler-marking that are synchronized in the ruler's rest frame. You can see from the diagrams how length contraction, time dilation and the relativity of simultaneity all work together to make it possible for the situation to be completely symmetrical, with each frame saying that the
other ruler is contracted and that the clocks on it are slowed-down and out-of-sync, without there being any contradictions in their predictions about local events like what times a given pair of clocks will read at the moment they pass next to one another.