ACTUAL Variation of Potential inside a diode.

AI Thread Summary
The discussion centers on the potential variation within a PN junction diode, challenging the conventional view that potential remains constant in the neutral P and N regions. It argues that the electric field from positive and negative charges extends into these regions, suggesting that potential should vary rather than remain constant. The user presents a new figure illustrating this potential variation, proposing that it decreases in a parabolic manner due to the relationship V=Q/4ΠΣr. The conversation also references a textbook that states there is no electric field in the neutral regions, reinforcing the idea that potential should be constant in those areas under unbiased conditions. However, when biased, the potential can change even in the neutral regions due to the presence of an external electric field driving current.
Amal Thejus
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Homework Statement


The figures showing the potential variation inside a PN junction normally shows the potential to be constant in the neutral P and N regions

Homework Equations



V=Q/4ΠΣr

The Attempt at a Solution


Since the potential due to the positive and negative charges should also exist in the neutral P and N region( since their electric field will definately extend to those regions and electric field and potential are directly related); i have come up with a new figure showing how the actual variation of potential in the neutral N and P regions will take place. I have attached the figure with this thread.
Figure showing the variation in potential from my textbook is also attached.[/B]
 

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Amal Thejus said:

Homework Statement


The figures showing the potential variation inside a PN junction normally shows the potential to be constant in the neutral P and N regions

Homework Equations



V=Q/4ΠΣr

The Attempt at a Solution


Since the potential due to the positive and negative charges should also exist in the neutral P and N region( since their electric field will definately extend to those regions and electric field and potential are directly related); i have come up with a new figure showing how the actual variation of potential in the neutral N and P regions will take place. I have attached the figure with this thread.
Figure showing the variation in potential from my textbook is also attached.[/B]

The electric field does not extend over the space charge region in case of an unbiased diode. In the neutral parts of the P and N regions, the electric field is zero, the potential is constant.
Think of a planar capacitor. There is charge on both plates ( equal and of opposite signs) but the electric field is non-zero only between the plates.
If the diode is biased, and current flows through it, there should be some electric field outside the pn junction that drives that current, as the semiconductor material has got some resistance. In this case, the potential changes even in the neutral region.
 
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ehild said:
The electric field does not extend over the space charge region in case of an unbiased diode. In the neutral parts of the P and N regions, the electric field is zero, the potential is constant.
Think of a planar capacitor. There is charge on both plates ( equal and of opposite signs) but the electric field is non-zero only between the plates.
If the diode is biased, and current flows through it, there should be some electric field outside the pn junction that drives that current, as the semiconductor material has got some resistance. In this case, the potential changes even in the neutral region.
It is said in the book 'Solid State Electronic Devices' by Ben G Streetman (page no.172) to ASSUME that there is NO electric field in the neutral regions.
Also since V=Q/4ΠΣr the potential should be present both inside the junction and in the Neutral region since 'r' can be taken in either directions.
My point was since v∝1/r the potential should NOT be constant and it should decrease in a parabolic manner.
 
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