Adding variables with same exponents

AI Thread Summary
The discussion centers on the expression .2y^3 + .6y^3 - .5y^3. The initial calculations confirm that combining the terms results in .3y^3. Participants agree on the use of the distributive law to simplify the expression. The final consensus is that the solution is correct at .3y^3. This confirms the proper method for adding variables with the same exponents.
rcmango
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Homework Statement



solve.

.2y^3 + .6y^3 - .5y^3

I believe the answer to be .3y^3

Homework Equations





The Attempt at a Solution



i got the answer to be .8y^3 - .5y^3

= .3y^3

I think this is correct, I'm not sure, please let me know if I finished this correctly.
 
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hi rcmango! :smile:
(try using the X2 button just above the Reply box :wink:)
rcmango said:
.2y^3 + .6y^3 - .5y^3

I believe the answer to be .3y^3

yes, that's fine :smile:

.2y3 + .6y3 - .5y3

= (.2 + .6 - .5)y3 = .3y3 (distributive law)
 
Thanks.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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