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Adiabatic Expansion - proof of PV^(gamma) = constant

  1. May 29, 2012 #1

    CAF123

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    Gold Member

    Hi,

    I was looking at the proof for the derivation of the condition satisfied by adiabatic processes. (The proof can be found in many introductory physics textbooks, I am using Principles of Physics HRW 9th ed.) At some point , they say 'For an ideal gas PV=nRT and if P,V T are allowed to take on small variations we have that PdV + VdP = nRdT'. Where does the part in bold come from, specifically the PdV +VdP?

    Sorry if I have overlooked something obvious.
     
  2. jcsd
  3. May 29, 2012 #2
    The derivative of product of variables. d(PV)=VdP +PdV
     
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