Adiabatic process thermodynamics help

AI Thread Summary
An ideal diatomic gas at 75 K is adiabatically compressed to 40% of its original volume, raising questions about determining its final temperature. The key equations for this problem include the adiabatic condition where Q=0, leading to delta U = -W, and the relationship PVγ = constant. The discussion highlights the need for the adiabatic equation in terms of temperature and volume, specifically TVγ-1 = constant, to solve for the final temperature without needing pressure. Understanding the value of γ is also crucial for solving the problem effectively. The conversation emphasizes the importance of combining thermodynamic principles to arrive at a solution.
uchicago2012
Messages
74
Reaction score
0

Homework Statement


An ideal diatomic gas at 75 K is adiabatically compressed to 40% its original volume. What is its final temperature?

Homework Equations


delta U = Q - W
W = the integral of PdV
PVgamma = constant
U = 5/2nKT = 5/2nRT (diatomic, ideal gas)

The Attempt at a Solution


So I'm having trouble because I don't know the pressure. I'm sure you can solve it without the pressure, but I didn't really see how to. Since it's an adiabatic process, Q= 0 so delta U = -W. I tried to write equations separately for U and W and set them equal to the negative of one another, but that ended badly, since the two equations were almost identical and everything, including my final temperature, divides out. Also, I wasn't sure if I can just solve for the problem using 1 mole as the amount present, but that's what I tried to do.
 
Physics news on Phys.org


You need the form of the adiabatic equation with T and V in it.
Do you have this in your notes or book?
It is derived by combining the one you mention, pVγ = constant, with pV/T = constant. [by division of one by the other to eliminate p]
 


uchicago2012 said:
PVγ = constant

Since you know this equation, you should probably know this one, too:

TVγ-1 = constant.

And you should know (or at least have in your textbook) the value of γ. Therefore, you can solve this problem fairly easily.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top