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Hello Fellow Physicists!
I'm having trouble with a problem from a graduate course in Statistical Mechanics. It's a two part question; I've got the first part, it's the second part that's giving me trouble.
The problem is about reversible/adiabatic processes, thinking of "reversible" as meaning "constant entropy." In part a (which I got, but it may help to have it here), we need to show that the evolution of a classical ideal gas obeys
[tex] TV^{\frac{2}{3}}=\mbox{constant.}[/tex]
I did this by using [tex]S=-\frac{\partial F}{\partial T}[/tex] with [tex]F=U-\mu N, U=\frac{3}{2}NT[/tex]. To get [tex]\frac{\partial \mu}{\partial T}[/tex], I solved
[tex] e^{\frac{\mu}{T}}=n\lambda^{3}=\frac{N}{V} \frac{h^{3}}{(2\pi mT)^{3/2}}[/tex]
for mu. ([tex]\lambda[/tex] is the thermodynamic wavelength, n is the number density of the gas.)
Now for part b. We have a classical ideal gas in a cylinder. It is in equilibrium at a temperature [tex]T_{0}[/tex]. Now we slowly (adiabatically and reversibly) apply a uniform external field to the container, in a direction along its axis of symmetry. When we are done, there is a potential in our container given by
[tex] u(z)=fz[/tex]
where z is the distance along that symmetry axis and f is a constant. The question is, what is the temperature of the gas at the end of the process?
I would think that we should use the same assumptions:
[tex]S=-\frac{\partial F}{\partial T}=\mbox{constant}[/tex]
and [tex]F=U-\mu N[/tex], but I don't know how u(z) gets incorporated into U. Any ideas?
Thanks for all of your time, everyone.
I'm having trouble with a problem from a graduate course in Statistical Mechanics. It's a two part question; I've got the first part, it's the second part that's giving me trouble.
The problem is about reversible/adiabatic processes, thinking of "reversible" as meaning "constant entropy." In part a (which I got, but it may help to have it here), we need to show that the evolution of a classical ideal gas obeys
[tex] TV^{\frac{2}{3}}=\mbox{constant.}[/tex]
I did this by using [tex]S=-\frac{\partial F}{\partial T}[/tex] with [tex]F=U-\mu N, U=\frac{3}{2}NT[/tex]. To get [tex]\frac{\partial \mu}{\partial T}[/tex], I solved
[tex] e^{\frac{\mu}{T}}=n\lambda^{3}=\frac{N}{V} \frac{h^{3}}{(2\pi mT)^{3/2}}[/tex]
for mu. ([tex]\lambda[/tex] is the thermodynamic wavelength, n is the number density of the gas.)
Now for part b. We have a classical ideal gas in a cylinder. It is in equilibrium at a temperature [tex]T_{0}[/tex]. Now we slowly (adiabatically and reversibly) apply a uniform external field to the container, in a direction along its axis of symmetry. When we are done, there is a potential in our container given by
[tex] u(z)=fz[/tex]
where z is the distance along that symmetry axis and f is a constant. The question is, what is the temperature of the gas at the end of the process?
I would think that we should use the same assumptions:
[tex]S=-\frac{\partial F}{\partial T}=\mbox{constant}[/tex]
and [tex]F=U-\mu N[/tex], but I don't know how u(z) gets incorporated into U. Any ideas?
Thanks for all of your time, everyone.