Aerosol Can Spray: Cooling Effects Explained

AI Thread Summary
Releasing spray from an aerosol can cools the can due to the Joule-Kelvin effect, which occurs when a real gas expands without heat exchange. As the gas escapes, the pressure inside the can decreases, leading to a drop in temperature according to the ideal gas law. The gas must pass through a smaller opening, causing this temperature variation. Discussions also touch on the entropy changes involved, noting that while the overall entropy increases, the specific entropy change of the can and its contents is questioned. Understanding these thermodynamic principles is essential for grasping the behavior of gases in aerosol applications.
alexbib
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I was told that when you release spray from an aerosol can, the can cools down. Is this true, and if so, why?

Does the gas in the can require outside energy to expand and escape the can?

Thanks,

Alex
 
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I think we can approach this problem with the good old ideal gas law. It states that P*V = n*R*T,

where P is pressure, V is volume, n represents the amount of gas, R is a constant, and T is temperature.

The gas in an aerosol can is under pressure. It wants to get out of the can and when you press the nozzle you provide the means for it to do so. Now were going to have to make some assumptions about what's going on when the nozzle is pressed and whatever gas is inside is sprayed out. I've only used this equation for gasses where n doesn't change. I think we can use a constant n as an approximation if we are considering a short burst. In this approximation the volume is going to remain constant as well (the can isn't changing shape) and R is defined as a constant. During the spray the pressure inside the can will go down, which for the above equation to be an equality, means the temperature has to go down.

Gabriel
 
That effect is known as Joule-Kelvin effect, and it only happens real gases! so the ideal gas don't work with this effect!

The Joule-Kelvin effect says that: If a real gas is expanding and it crosses a (i don't know the english word, but i want to mean that the section of the tube or so is lower than the section the gas was crossing before), without interchange of heat, then the temperature variates.

When you press the aerosol, the gas has to cross through the little hole, so the temperature of the recipient goes down.

MiGUi.
 
alright, I'll look it up. thanks!
 
this is exactly refrigirator work!
 
hey, anybody knows what happens to the entropy of the can? Does it increase or decrease? How could you evaluate the change in entropy, since pV=nRt is not true?
 
it is obvious that the overall entropy change is positive (compressed gas in a can is more ordered than when the pressure reaches an equilibrium, but what about the entropy of the can (and it's content) alone?
 
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