Agravic Point Calculation Between Earth and Mars

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The discussion focuses on calculating the agravic point between Earth and Mars, where their gravitational forces balance. The original poster struggles with deriving a formula and encounters issues with a quadratic equation yielding no real solutions for large distances. Clarification is sought on whether a custom coordinate system can be used, with Earth at the origin. A participant points out an error in the quadratic formula application, specifically in the coefficients, which resolves the issue. The conversation concludes with the original poster gaining clarity on the calculation process.
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Ok, this extra credit assignment is driving crazy. I keep trying to put it away and work on something important, but it can't get it out of my mind.

The full question is:
On the agonic line between Earth and Mars lies the agravic point with respect to the gravitational fields of the two planets. Determine the location of that point as a function of the locations of both Earth and Mars.

I assume they are talking about the point between the planets where the force of gravity of the Earth equals the force of gravity of mars.

I've tried a few different things to get a formula that would tell me how far from Earth the point would be if the distance between them was known. It keeps leading me to a quadratic with no real solution if the distance between them is large.

Even if I can figure out what I'm doing wrong there, I'm not totally sure it's what the question is asking. What do they mean by "as a function of the locations of both planets"? Shouldn't I be free to set up my own coordinate system with Earth at the origin?

Here's what I have so far:

G = gravitational constant
Me = mass of Earth
Mm = mass of Mars
x = distance between the center of the Earth and the agonic point (I think this should end up being the dependant variable)
d = distance between the Earth and Mars (I think this should be the independent variable)

Since I want to find the point where the gravitational field of the Earth is equal to the gravitational field of Mars, I set them equal to each other.

\frac{G*Me}{x^2}=\frac{G*Mm}{(d-x)^2}

The G's cancel, after a little algebra, I end up with:

d^2-2dx+(x^2-\frac{Mm}{Me}x^2)

If I try to solve this for x I end up with a negative under the square root sign if d is large.

Can someone help me out with this? Am I even getting close?
 
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"If I try to solve this for x I end up with a negative under the square root sign if d is large."

I don't see why you would. Using the quadratic formula, the "discriminant" (b2- 4ac) for this equation is
4d^2- 4(1-\frac{M_m}){M_e}d^2}= 4d^2(\frac{M_m}{M_e}).

That's positive as long as the masses are!
 
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Thanks, I see it now. I had used B=-2 instead of B=-2d and then just kept making the same mistake over an over.
 
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