Air Compression vs Water Depth

AI Thread Summary
The discussion centers on the effects of water depth on air compression in a small diving bell made from a pickle jar. At a maximum depth of 10 meters, the air volume in the jar will be halved due to increased pressure, which is approximately 1 atmosphere for every 10 meters of depth. The user expresses concern about the usable space for their equipment inside the jar and contemplates needing a larger container. It is clarified that water pressure acts uniformly, meaning the integrity of the glass will not be compromised by the pressure difference. The conversation highlights the importance of understanding basic physics and pressure principles for successful project execution.
TjFitz
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Hey ya,

Well, I have been having a difficult time finding the answer to this question, probably because I don't know the specific terminology. So here I am. I did not know exactly which forum category to put this in so...

I am building a small diving bell with a remote controlled camer inside. Nothing more than a hobby project..

The Bell is actually nothing more than a 1 liter Pickle Jar.

What I am wondering is, how much compression of air can I expect at let's say a max of 10 meter depth. meaning if I have 1 liter of air in the jar, how far will that compress per meter fresh water depth.

I would like to know this because I need to know how much room in the jar I have that I can use, or even how deep I should limit myself before water would reach my gear in the jar.

is there a simple equation which states X cc/ml of air compression per meter depth?
 

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pV=nRT is all you need. Or even pV=const will do.

In general - look for ideal gas equation.

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Borek
Thanks for your quick response... But what does it all mean...? I am basically an idiot in this :bugeye:
 
Yes, you can calculate exactly what the water pressure will be. If you are interested it is simple. If not, then you can use a diving rule of thumb of 1 atmosphere per every 10 meters of depth (it's within about .5 psi depending on a few things). At 10 meters you'll basically be doubling your pressure, therefore halving your volume which sounds like more than accurate enough for what you want to do.
 
sorry about my delayed responses, I believe there is an anti spammer thingy.. as a newbie my posts have to get approved first. all good..

SH. Ouch.. so, given the ballpark figure, I am filling half my jar at 10m.. looks like I am going to need a larger jar.. otherwise I am going to run out of useable dry space...
 
ok... one last question. (Promise I'll come back and show what I built)

Would the integrity of the glass (where the air is trapped) be acted upon in the same respect or would it only be effected by the same boyancy as when on the surface.. meaning, is the pressure of the water going to press on the glass or just where the water meets the air inside?

Oh.. and I Wiki'd the pV=nRT.. now it makes sense to me! Thanks B.
 
Pressure will be identical everywhere - which means you don't have to worry about it.

I feel like you will benefit from some reading about pressure and basic physics in general.
 
I do agree that I have a bit of reading to do. the only problem has been that most reading in physics as well as other scientific arenas, the authors asume you know so much already which I dont. I understand a lot and am quick to pick up things, I am often times at a loss for the starting info.. yaknow?

appreciate your help.
 

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