Air Hockey Table Inclination Calculation

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The discussion revolves around calculating the inclination of an air hockey table based on the puck's motion. A physics student observes that a puck, given an initial velocity of 3.82 m/s, drifts 2.47 cm to the right while traveling 1.65 m along the table. Despite initial confusion about the problem's complexity, it is clarified that the situation can be analyzed as a two-dimensional problem due to the absence of friction. The only force acting on the puck is gravity, allowing for the use of kinematic equations to derive the acceleration across the table. Ultimately, the inclination is determined to be a small angle, aligning with intuitive expectations.
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Homework Statement



A physics student playing with an air hockey table (a frictionless surface) finds that if she gives the puck a velocity of 3.82 m/s along the length ( 1.65 m) of the table at one end, by the time it has reached the other end the puck has drifted a distance 2.47 cm to the right but still has a velocity component along the length of 3.82 m/s. She concludes correctly that the table is not level and correctly calculates its inclination from the above information.

Homework Equations





The Attempt at a Solution


I don't even know where to start! It has to be solved in three dimensions and I'm having trouble setting it up.
 
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this problem could be a lot simpler than you first think. At first sight, admittedly, it looks like a 3d vector problem. However, given that there is no friction, and the only force affecting the motion is the weight, it is in fact a 2 - dimensional problem. The vertical plane (with weight "visible") is where the mechanics goes on, and the motion along the table is useful for one thing only - calculating the transit time. There is no force in this direction.

Try drawing a diagram representing the puck as a particle and the table as a line at an angle to the vertical. The only force acting is weight. Draw this force on. Now, try and derive an equation for the acceleration "sideways" across the table. Bearing in mind about what I said earlier about using the other direction to calculate the time, you should easily be able to just use kinematic equations of motion, and it's a fairly simple problem. Good luck
 
by the way, the answer I get for this problem is quite a small angle, which is probably intuitively what one would expect!
 
I got it figured out, thanks!
 
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