Algebra 101, and some about complex numbers

AI Thread Summary
The discussion centers on the equation involving complex numbers, specifically the misunderstanding of why the expression c^2 - (d^2 * i^2) simplifies to c^2 + d^2 instead of c^2 - d^2. It clarifies that i is the imaginary unit defined as the square root of -1, meaning i^2 equals -1. Therefore, substituting i^2 into the equation changes the sign of the d^2 term, leading to the correct expression of c^2 + d^2. The participant realizes that their confusion stemmed from a misunderstanding of the properties of complex numbers rather than algebra itself. This highlights the importance of grasping the fundamentals of complex numbers in algebra.
Keba
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Homework Statement


I was looking up complex numbers and the guy on YouTube made something similar to this equation:
i=-1
c^2-(d^2*i^2) = c^2+d^2

( - 2:55)

Homework Equations


I do not understand why it is "c^2+d^2" and not "c^2-d^2"
I would like a detailed explanation, as I might have misunderstood algebra somehow

The Attempt at a Solution


I would do this to find a solution
c^2-(d^2*i^2)
c^2-(d^2*(-1)^2)
c^2-(d^2*1)
c^2-d^2
 
Last edited by a moderator:
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The general form of a complex nr is ;a+bi, where i is the imaginary.

it is the square root of negative one, that is:

\sqrt{-1}=i=>i^2=-1 now going back to what u have there

c^2-(d^2i^2)=c^2-(d^2(-1))=c^2+d^2
 
I see, so my problem wasn't with algebra but with my understanding of complex numbers.
Then it makes perfect sense! I thank you good sir =P
 
Keba said:

Homework Statement


I was looking up complex numbers and the guy on YouTube made something similar to this equation:
i=-1
Here was your error. i is NOT -1. Its square is -1: i2= -1.

c^2-(d^2*i^2) = c^2+d^2

( - 2:55)

Homework Equations


I do not understand why it is "c^2+d^2" and not "c^2-d^2"
I would like a detailed explanation, as I might have misunderstood algebra somehow

The Attempt at a Solution


I would do this to find a solution
c^2-(d^2*i^2)
c^2-(d^2*(-1)^2)
c^2-(d^2*1)
c^2-d^2
 
Last edited by a moderator:
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