Algebra: How do I derive this equation given two other equations?

AI Thread Summary
The discussion revolves around deriving equation (5) from two other equations, with the user initially struggling due to a misunderstanding of the terms involved. They noted that their partial derivative was incorrectly multiplied by mu instead of being squared, and they lacked a factor of 1/2. After receiving clarification, they realized that the correct interpretation involved the derivative of mu squared rather than the square of the derivative. This revelation allowed them to identify their mistake and conclude that the question could be closed. The exchange highlights the importance of precise mathematical notation in derivations.
dsilvas
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Homework Statement
Derive eq.(5) and eq.(6) from eq.(3) and (4)
Relevant Equations
Unsure how to type the equations correctly in this text box (no formating options). They are below.
hw9.JPG

This image shows the equations.
I managed to almost get equation 5, but my partial derivative is not squared but instead multiplied by mu, and also I don't have a factor of 1/2.
Here is an image of the work I have. I'm sorry for any sloppiness. I tried to be as concise as possible when writing it down but it should be pretty straightforward. Essentially the only way my final equation could be equal to eq.(5) is if mu is equal 1/2 of its partial derivative with respect to r.
hw9_mywork.jpg

If it helps, here is the link to the paper that these equations are coming from. It is page 2.
https://agupubs.onlinelibrary.wiley.com/doi/epdf/10.1029/98RS01523
I didn't write it out explicitly, so to elaborate, r prime in my work is equal to the full derivative of r with respect to theta. I was able to derive eq. (6) from eq. (4) and that has helped me get closer to deriving eq. (5) but I'm not quite there and I'm stuck.
 

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Hi.
In the last line in your notebook substitute
\mu \frac{d\mu}{dr}=\frac{1}{2}\frac{d\mu^2}{d\mu}\frac{d\mu}{dr}=\frac{1}{2}\frac{d\mu^2}{dr}
 
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mitochan said:
Hi.
In the last line in your notebook substitute
\mu \frac{d\mu}{dr}=\frac{1}{2}\frac{d\mu}{dr}

Oh gosh. I think I realize my mistake now, thank you.
I assumed in eq 5 that it was {(\frac{d\mu}{dr})}^2 when in reality it was \frac{d(\mu^2)}{dr}
I just can't read. Thank you. I didn't realize it was that simple.

I guess this question can be closed now!
 
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