Draw Lattice Diagram for K: Solving Algebra I Mapping Homework

rbzima
Messages
83
Reaction score
0

Homework Statement



K = {x C S7 | 2x=2, {1,4}x={1,4}, {1,5,7}x={1,5,7}}.
Draw Lattice Diagram for K.2. The attempt at a solution

I've looked at this for about 30 minutes and came to the conclusion that there are 140 unique solutions to this mapping, and I know for a fact that the professor does not want us to draw all 140 of these. Essentially, I found that 3!3!2!2! - 4 = 140. At this point I have no idea how to express this in a far easier form then what is given and I'm not sure where to go with the Lattice Diagram. Help would def be appreciated.
 
Physics news on Phys.org
Never mind. Mods can delete this thread because I've figured it out. The statement above states that {1,4}x = {1,4}, but similarly {1,5,7}x = {1,5,7}, which implies that for this statement to be true, 1 maps to 1, and 4 maps to 4, therefore all we are left with is combinations of {5,7} and {3,6}, which are simply (57)(36), I(36), (57)I, and I sub 7.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top