Algebra Inverse Function Problem

AI Thread Summary
The discussion centers on finding the inverse of the function f(x) = (x-3)² - 1, specifically for the domain x ≥ 3. The participant seeks clarification on how the condition x ≥ 3 affects the inverse function. It is noted that this condition limits the domain and is crucial for determining the correct inverse. To find the inverse, one must solve the equation y = (x-3)² - 1 for x, taking into account the specified domain. Understanding these constraints is essential for accurately deriving the inverse function.
nordqvist11
Messages
15
Reaction score
0

Homework Statement


f(x)=(x-3)^2 -1 for x ≥3


Homework Equations





The Attempt at a Solution


I am having difficulty grasping the concept of changing the greater than or equal to part of the equation above to it's inverse form. If for x it says x≥3 then how would that statement be relevant to finding the inverse of the function. In other words, I need clarification as to how that specific aspect of the equation changes in inverse form.
 
Physics news on Phys.org
Well, what does the condition x≥3 mean for the equation f(x)=(x-3)^2 -1 ?
 
That the domain is limited and does not include all real numbers for the function. I guess it sets a domain limit?
 
Show what steps are needed to solve y=(x-3)2 -1 for x.
 

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
View full post »

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
View full post »

Similar threads

State the domain and range for a given function
Replies
7
Views
2K
Composite and Inverse Functions Problem
Replies
3
Views
2K
To find the range of a given ##\sin## function
Replies
15
Views
2K
Domain and Range of a Function and Its Inverse- Polynomials
Replies
9
Views
2K
Finding the inverse of ##y=2^{x}##
Replies
19
Views
3K
Find the inverse function of ##f(x) =x^4+2x^2##
Replies
11
Views
3K
Find the function that matches the equation
Replies
9
Views
2K
Prove an equation involving inverse circular functions
Replies
6
Views
2K
Calculating Inverse Functions for Hourly Salary and Production Units
Replies
6
Views
2K
A problem in Inverse Circular Functions in Trigonometry
Replies
9
Views
2K

Hot Threads

Recent Insights

Back
Top