- #1
They are using the quadratic formula. The expression in blue is what's inside the radical in this formula, the expression b2 - 4ac.Miike012 said:I would like to know how the book went from the term highlited in red to the term in blue.
This doesn't make any sense, because 2 is not greater than 6. I think what they are saying is the either y < 2 OR y > 6.Miike012 said:The book is saying... if 2> y> 6
Miike012 said:then there will be real roots ( I think ).
What does this have to do with the original equation (x^2 +2x - 11)/(2(x-3)) ?
Miike012 said:When I took the original equation and set it eqaul to 2 I got (x - 1)^2
=6 I got (x - 5)^2
Thus when y = 2 there is only one root of 1
y = 6 there is only one root of 5...
Is this what they are saying? And why would this matter? There must be something I am not seeing.
Miike012 said:The book is saying... if 2> y> 6 then there will be real roots ( I think ).
What does this have to do with the original equation (x^2 +2x - 11)/(2(x-3)) ?
Mark44 said:Notice that if y = 2 or y = 6, there will be only a single real root of the quadratic equation.
Mark44 said:From post #4.
Miike012 said:And this is important why? How is this applicable? How will knowing this information help me?
Miike012 said:And this is important why? How is this applicable? How will knowing this information help me?
Miike012 said:Ok. So this what ever it is, I don't know what to call it, seems like a waste of space in an alg book.
I guess right now, seeing that I will be starting calc 1, will have not benefit to me.
NascentOxygen said:Come back in 6 months and tell us whether you're right.
"Solving Algebra: Red to Blue" is a problem-solving technique used in algebra to simplify equations and solve for a variable. It involves isolating the variable on one side of the equation and rearranging the terms in a specific order to solve for its value.
"Solving Algebra: Red to Blue" is typically used when solving linear equations with one variable. It can also be useful in solving systems of equations or equations with multiple variables, but these may require additional steps.
The steps to solve an equation using "Solving Algebra: Red to Blue" are:
1. Simplify both sides of the equation by combining like terms.
2. Move all terms containing the variable to one side of the equation.
3. Move all constants to the other side of the equation.
4. Divide both sides by the coefficient of the variable to isolate the variable.
5. Check your solution by plugging it back into the original equation.
One common mistake is forgetting to perform the same operation on both sides of the equation. It is important to maintain balance on both sides to ensure the equation remains equivalent. Another mistake is not distributing the negative sign properly when moving terms to the other side of the equation.
No, "Solving Algebra: Red to Blue" is specifically designed for solving linear equations with one variable. It may not be applicable for more complex equations involving exponents, radicals, or logarithms. In these cases, other problem-solving techniques may be more effective.