- #1

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Sub in t as [itex]x^{\frac{1}{2}}[/itex]

[itex]4x+8=33x^{\frac{1}{2}}[/itex]

I just don't see how to do this without a calculator.

If I take t^2=x, then sub it in I need to do the quadratic formula which is too hard without a calculator/would take too long in an exam. Even if I do the formula I get t=8,2 which I would then need to square route to get x but would be the wrong answer since x = 64 and 1/16....

Any help. Is t^2=x a wrong assumption? Surely it is right since x^1/2 squared gives x?