Allowed Eigenstates for a particle question

Dindimin09
Messages
6
Reaction score
0
Screen Shot 2014-07-30 at 15.16.23.png
 
Physics news on Phys.org
So? What have you done? What are the relevant equations? You won't get help on this forum by just posting a problem!
 
You will have to excuse my ignorance I am very new to Physics Forum and relatively so to QM. Please accept my apologies.

So inside the box V=0,
Thus ψ = Ae^ikx +B-ikx = Ccoskx + Dsinkx

Outside the box V = ∞ therefore ψ = 0
if ψ is continuous it must be zero at the edges of the box

→ ψ(0) = 0 and ψ(L) = 0
For ψ(0) = 0 then C = 0 therefore ψ(x) = Dsin(kx)

These boundry conditions lead to eigen functions in the form ψ(x) = Dsin(kx) and quantised values of k=n∏/L leading to quantised values of E given by:
E = hbar^2n^2/8mL^2

However if the eigenfunctions must be completely specified we normalize them:

→∫ψ*ψ dx = D^2sin^2(kx)dx=1 where D=√(2/L)= An and L=W

→ψn(z) = Ansin(n∏z/w)

Thanks for your help.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top