Alpha Particle Kinetic Energy: Explained

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Discussion Overview

The discussion revolves around the kinetic energy of alpha particles in relation to the nuclear potential well. Participants explore the relationship between the kinetic energy of an alpha particle, the depth of the potential well, and the implications of tunneling effects in nuclear physics.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the calculation of kinetic energy inside the nucleus, suggesting it involves subtracting the potential well depth from the kinetic energy outside.
  • Another participant proposes that the correct relationship might be T-V or T+V, depending on how the depth of the potential well is defined.
  • A participant asserts that the energy needed for the alpha particle to escape is related to its kinetic energy outside and suggests that the energy inside the nucleus should be T+E, where E is related to the potential well.
  • One participant introduces the concept of tunneling, arguing that an alpha particle can escape even if its energy is lower than the potential well, challenging the idea that it must have energy greater than or equal to the potential well to escape.
  • Another participant clarifies that all alpha decays occur via tunneling and emphasizes the importance of the energy difference between the inside of the nucleus and far away from it.
  • A later reply questions whether the potential well depth should be considered negative if the energy outside is expressed as T+V.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between kinetic energy and potential well depth, with no consensus reached on the correct formulation. The discussion remains unresolved regarding the implications of tunneling and the definitions of energy in this context.

Contextual Notes

Participants have not fully agreed on the definitions of potential well depth or the signs associated with energy calculations, leading to ambiguity in their discussions. The implications of tunneling are also not settled, as participants present varying interpretations.

Manel
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i'm struggling to understand this:
an alpha particle is emitted with a kenetic energy T, if we know the value of the depth of the nuclear potential well V, we find the kenetic energy of the alpha particle inside the nuclei by substructing V-T , would you please explain this to me? Thank's
 
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"substructing" is subtracting?
I think this should be T-V. Or T+V, depending on the sign definition of "depth".
 
the depth is positive,the problem is that i don't get why? i found V-T?
 
Well, the particle needs an energy E to get out. So if it has T outside, it had T+E inside. Now you can identify E with + or - V.
 
so it's not V-T (because i couldn't get why) but if it's V+T i accept it, i thought that the particle can get out even if it has an energy lower than the potential well because of tunneling effect! according to what you said it must have an energy greater or equal to it! is that right?
 
Wait... I always used the energy difference between "inside the nucleus" and "far away from it". The potential wall in between is something different.
If the alpha particle would have an energy larger than the potential wall, the nucleus would not exist at all (no bound state). All alpha decays are via tunneling.
 
ok, i get that, so if we say: the energy outside is equal to T+V (taking V positive) we will get an energy for the alpha particle greater than the potential wall..in other words V is negative?
 

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