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Alternatic Current Derivation

  1. Nov 14, 2011 #1
    Hello all,
    I'm trying to find the derivation for the alternating signal. For example,
    Untitled-9.jpg
    let b=width of loop
    a=length of loop
    Hence,
    [tex]ε=vLB=vaB=ωraB=\frac{1}{2}ωabB=\frac{1}{2}ωAB[/tex]
    I cannot seem to find the derivation of how one gets from this step, to the sinusoidal waveform. Any help is greatly appreciated.
     
  2. jcsd
  3. Nov 14, 2011 #2
    Your sin comes from the fact that in the up and down direction V has a magnitude that varies sinusoudally. ie At the top and bottom, 0 deg and 180 deg, if y is the vertical direction , Vy=0. At 90 deg and 270 deg Vy has its maximum value wr.
     
  4. Nov 14, 2011 #3
    So, essentially the first part of the derivation has nothing to do with the rest? My notes jump from the first part that I depicted directly to the sinusoid function, without any intermediate steps.
     
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