Altitude of a Rocket Launched into Space

AI Thread Summary
A 4.60 kg rocket is launched upward from Earth at a speed of 9.00 km/s. The relevant equation used to determine the altitude is v = √(2GM/r), where G is the gravitational constant. The calculation yielded a radius of 6.8 x 10^-14 m, indicating the height needed to escape Earth's gravitational pull. The mass of the rocket is irrelevant in this context, as all objects in freefall accelerate uniformly. This discussion highlights the application of escape velocity in determining the altitude necessary for a rocket to leave Earth's gravitational influence.
tesla93
Messages
22
Reaction score
0
The Problem:

A 4.60 kg rocket is launched directly upward from Earth at 9.00 km/s

What altitude above the Earth's surface does the rocket reach?


Relevant Equations:

v = √ (2GM/r)

The Attempt:

m = 4.60 kg
v = 9km/s = 9000m/s
G = 6.67 x 10^-11

9000^2 = 2(6.67^-11)(4.60)/r

r = 6.8 x 10-14m

I used that formula because it is for escape speed, which I think applies to this question, as it needs to be a certain height above the Earth to escape the pull and stay in orbit.
 
Physics news on Phys.org
"M" is the mass of the Earth, not of the rocket. The mass of the rocket doesn't matter because in freefall, all objects accelerate at the same rate, regardless of mass.
 
Oh alright that makes sense. Thank you!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top