LLT71 said:
I want to ask you this one more question. why do we need "1+ part" in:
y(t)=[1+m(t)]*c(t)
Good question. I had actually forgotten about this until I tried to explain AM to someone in a previous thread. I had just remembered the general principle of (amplitude) modulation as multiplication.
I think back to how one did AM in old valve transmitters (yes, I'm that old!) We used to take the power amplifier valve, with its high +ve voltage on the anode and use a transformer in series with the high voltage supply. By applying the audio signal to the primary of the transformer, the audio voltage was added to the high voltage via the secondary. So If the valve had a quiescent voltage of say +100V and you applied 50V (AC) of audio, the anode voltage varied between +150V and +50V as the audio voltage varied between +50V and -50V.
The anode voltage determined the amplitude of the RF output, so the RF output was proportional to the audio voltage added to the quiescent high voltage. The 1+ part of the formula represents this quiescent (or average, or standing) high voltage applied to the anode and the m(t) represents the audio voltage added to it by the modulation transformer. The sum of these is the instantaneous anode voltage, which determines the output amplitude of the c(t) carrier signal.
(1+m(t))*c(t) , when m(t)=0 you have unmodulated RF ( ie c(t) ).
When the amplitude of m(t) =1 or the same as c(t) you have 100% modulation
and the envelope is 1+m(t), (here a sinewave)
You could increase the audio drive up towards 100V (AC) causing the anode voltage to vary between 0V and +200V. If you increased the audio drive beyond that, the the anode voltage would become negative for part of the audio cycle, which would make the valve "cut off", since it only functions with a positive voltage on the anode.
So the amplitude of the audio signal was not allowed to exceed the quiescent anode voltage. In the formula this quiescent voltage is factored out, so that it is represented by 1 and the magnitude of m(t) is always less than 1. (Since in practical terms you don't actually get a valve or transistor to operate to 100% modulation, because there would be no voltage on the anode, collector, drain or whatever.)
If the amplitude of m(t) is greater than that of c(t), then you have over-modulation, causing distortion.
This shows the calculated (1+m(t))c(t) and the envelope no longer reproduces the sinewave. In a transmitter, the part where (1+m(t)) is negative would cut off the PA device and the graph would be flat here rather than inverted.
If there were no 1+ in the formula, then any amplitude of m(t) would produce negative values of (0+ m(t)) and you would never get a clean envelope.
The value has to be 1 simply because that represents the amplitude of c(t) and the maximum allowable amplitude of m(t).BTW. The wild comment at the end of my previous post (about maybe transmitting a beat signal rather than a modulated one, is rubbish! ( It was very late, blah, blah, etc.) What I'd not thought of was, that you won't even get beats unless the frequencies are close - which will never be the case for audio and RF. (I'd just accepted without thinking, the proposition that you got beats between any frequencies.) With close frequencies you get half the sum (mean) modulated by (sort of) the difference (frequencies.) Once the frequencies become too far apart, the difference frequency is bigger than the mean frequency, so the result looks nothing like one modulating the other.
Now if you have two radio frequencies which are close, they do indeed produce beats, which were heard as annoying whistles in AM receivers. And they were used, as musicians use audio beats, to adjust two transmitters to the same frequency by listening for zero beat.