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qn. The amplitude of vibration of a certain sound wave is increase by 50%. What is the corresponding increase in the decibel level of the sound?

My attempt..

beta= 10 log ( I/Io)

lets just take I = 2.0 x 10^-7

let just take Io= 1.00 x 10^-12

then 10 log( 2.0 x 10^-7/1.00 x 10^-12) = 10 log (2.0 x 10^5) = 53db

if we increse I by 50 % = (2.0 x 10^-7) x 1.5

= 3.0 x 10^-7

then

10 log( 3.0 x 10^-7/1.00 x 10^-12) = 10 log (3.0 x 10^5) = 54.8 db

so the change of decibel = 54.8db - 53db = 1.8db

correct attemp this question this way??

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# Homework Help: Amplitude of sound wave in by 50%

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