Amplitude of velocity (Travelling wave)

AI Thread Summary
The wave traveling along a string is described by the equation y(x,t) = 20sin(3x - 2t). To find the amplitude of the velocity of any particle of the string, the partial derivative with respect to time is calculated, yielding ∂y/∂t = -40cos(3x - 2t). This indicates the amplitude of the velocity is 40 m/s, as the negative sign indicates direction rather than magnitude. There is a discussion about the lack of units for y, with some participants noting that 20 m seems large for a wave amplitude on a string. Overall, the calculation is confirmed to be correct despite the unit ambiguity.
Alex_Neof
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Homework Statement


A wave traveling along a long string has the form:

##y(x,t) = 20sin(3x - 2t),

## where ##x## is in metres and ##t## is in seconds.

Find the amplitude of the velocity of any particle of the string.

2. Homework Equations


Do I just find ##\frac {\partial y}{\partial t} ## ?

The Attempt at a Solution



So ##\frac {\partial y}{\partial t} = -40cos(3x - 2t) ##, therefore the amplitude of the velocity of any particle of the string is ##-40 m/s##. Absolute value ##40 m/s##.
Or is it more involved?
 
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Your work looks good to me. However, the units for y are not given. 20 m seems like a very large amplitude for a wave on a string. :wideeyed:
 
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ahaha !. The :wideeyed: is making me laugh. Yeah the question didn't give the units for y. Thanks TSny.
 
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