How Does A.H. Pfund's Method Determine the Refractive Index of Glass?

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A.H. Pfund's method measures the refractive index of glass using a slab with one painted face and a small clear hole as a light source. The critical angle leads to total internal reflection, creating a dark circle surrounded by an illuminated halo. The refractive index is calculated using the formula n=(1+(16t^2)/d^2), with specific values yielding a diameter of 2.09×10(-2)m for a slab thickness of 0.06 cm. When using white light, dispersion affects the critical angle, causing the inner edge of the halo to appear tinged with violet light due to its higher refractive index. Understanding this relationship highlights how color dispersion relates to the refractive index and critical angle in optics.
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Homework Statement


An A.H. Pfinds's method for measuring the index of refraction of glass is illustrated in the figure. One face of a slab of thickness t is painted white, and a small hole scraped cleat at point P serves as a source of diverging rays when the slab is illuminated from below. Ray PBB' strikes the clear surface at the critical angle and is totally elected, as are rays such as PCC'. Rays such as PAA' emerge from the clear surface. On the painted surface, there appears a dark circle of diameter d surrounded by an illuminated region, or halo.

diagram: https://dl.dropbox.com/u/77575413/68.png

Part A:
The equation for n in terms of the measured quantities d and t. is n=(1+(16t^2)/d^2)^(1/2)

Part B:
The diameter of the dark circle if n=1.52 for a slab of 0.06 cm thick is 2.09×10(-2)m

Part C:
If white light is used, dispersion causes the critical angle to depend on color. Is the inner edge of the white halo tinged with red light or with violet light explain.

Homework Equations



n=(1+(16t^2)/d^2)^(1/2)

The Attempt at a Solution



I was able to do part A and B but I am not sure about Part C.

I said the white halo is tinged with violet light since violet light has a higher index of refraction. Is this true or did I mess up.
 
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