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An indefinite integral

  • Thread starter mrdoe
  • Start date
  • #1
36
0
Find
[tex]\displaystyle\int\dfrac{\sec ^2\sqrt{x}}{\sqrt{x}} dx[/tex]
We're supposed to use u du substitution but I can't seem to get this one.

EDIT: Sorry I didn't read rules.

I tried [tex]u=\sec^2\sqrt{x}[/tex] and all variants. Usually it was in the form of

[sec or cos][^2 or none][sqrt x]
 

Answers and Replies

  • #2
Defennder
Homework Helper
2,591
5
Well a more intuitive substitution would be to take [tex]u=\sqrt{x}[/tex].
 
  • #3
36
0
thanks, I can't see why I didn't see that :surprised
 

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