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[tex]\displaystyle\int\dfrac{\sec ^2\sqrt{x}}{\sqrt{x}} dx[/tex]

We're supposed to use u du substitution but I can't seem to get this one.

EDIT: Sorry I didn't read rules.

I tried [tex]u=\sec^2\sqrt{x}[/tex] and all variants. Usually it was in the form of

[sec or cos][^2 or none][sqrt x]

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# Homework Help: An indefinite integral

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