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An indefinite integral

  1. Jan 6, 2009 #1
    Find
    [tex]\displaystyle\int\dfrac{\sec ^2\sqrt{x}}{\sqrt{x}} dx[/tex]
    We're supposed to use u du substitution but I can't seem to get this one.

    EDIT: Sorry I didn't read rules.

    I tried [tex]u=\sec^2\sqrt{x}[/tex] and all variants. Usually it was in the form of

    [sec or cos][^2 or none][sqrt x]
     
  2. jcsd
  3. Jan 6, 2009 #2

    Defennder

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    Well a more intuitive substitution would be to take [tex]u=\sqrt{x}[/tex].
     
  4. Jan 6, 2009 #3
    thanks, I can't see why I didn't see that :surprised
     
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