# An indefinite integral

Find
$$\displaystyle\int\dfrac{\sec ^2\sqrt{x}}{\sqrt{x}} dx$$
We're supposed to use u du substitution but I can't seem to get this one.

EDIT: Sorry I didn't read rules.

I tried $$u=\sec^2\sqrt{x}$$ and all variants. Usually it was in the form of

[sec or cos][^2 or none][sqrt x]

Well a more intuitive substitution would be to take $$u=\sqrt{x}$$.