Analysis 2- Riemann integrable functions

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SUMMARY

The discussion centers on the Riemann integrability of functions, specifically addressing the statement: "If |f| is Riemann integrable on [a,b], then f is Riemann integrable on [a,b]." Participants concluded that this statement is false, providing reasoning based on the definition of Riemann integrability. A counterexample is suggested as a method to demonstrate the falsehood of the statement, emphasizing the necessity of boundedness and the epsilon-delta criterion in Riemann integration.

PREREQUISITES
  • Understanding of Riemann integrability and its definitions.
  • Familiarity with the concepts of bounded functions on intervals.
  • Knowledge of partitions and upper/lower sums in integration.
  • Ability to construct counterexamples in mathematical proofs.
NEXT STEPS
  • Research the properties of Riemann integrable functions and their implications.
  • Study the epsilon-delta definition of Riemann integrability in detail.
  • Explore counterexamples that illustrate non-integrable functions.
  • Learn about Lebesgue integration as an alternative to Riemann integration.
USEFUL FOR

Mathematics students, educators, and anyone studying real analysis or integration theory will benefit from this discussion.

perlawin
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1. If abs(f) is Riemann integrable on [a,b], then f is Riemann integrable on [a,b]. True or false (show work)



2. A function f is Riem Int iff f is bounded on [a,b], and for every epsilon>0 there is a partition P of [a,b] s.t. U(f,P)-L(f,P)<epsilon



3. I believe that this is true. So, what I want to do is show that f is bounded don [a,b], and I also want to show the second part of the definition. To show it was bounded, I used the fact that abs(f) was bounded and eventually got sup(abs(f))<=sup(f) and inf(f)>=-sup(abs(f)), which *I think* proved that f is bounded.

My question is how do I show that it fits the second part of the definition?
 
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You can't show the second part. Because it isn't true. Try to find a counterexample.
 
I'm not sure what the question is and what's your answer. However the statement "if abs(f) is Riemann integrable on [a,b] then f is Riemann integrable on [a,b] isn't true."
 

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