1. The problem statement, all variables and given/known data 2. Relevant equations See above picture. 3. The attempt at a solution I am stuck on the first part, i know i need to find the x intercept of the DC load line is at +Vcc, and I am pretty sure the y intercept is at Vcc/R7, but I do not know how to use this information to find the Q point. The Q point is the current and Vce drop when there is no input signal. So i think i am supposed to assume that Vin is 0V and see what that gets me. Well if Vin is zero volts then Vb of Q1 is 0V which means Ve of Q1 is -0.7 volts. From this we can find the current through R5 because the it should equal (-0.7 - -Vcc)/R5. I am now wondering if that means the the current through R4 is also this amount because the collector current is approximately the same as the emitter current. But i have no idea, furthermore i don't know how to use this information to help me determine the Q point of Q3 (i am really just spitballing). Any help is much appreciated! EDIT: So i believe i have a different approach to solving part a. If we assume negligible current goes into the base of each transistor we can use a voltage divider to find the voltage at the base of Q1, this would be Vcc *[R3/(R1+R2+R3)], lets call this Vb. Now we use the standard diode drop 0.7 to find the voltage of the emitter. Then using the above method for finding current through the emitter resistor of the Q1 we find that Ie = (Vb-0.7-(-Vcc))/R4. So this is the current through the emitter resistor. I don't know if we can assume this is also the current through the collector resistor of Q1, but if it is we can simply find the voltage at the collector of Q2 via Vcc - Ie*R4. This gives us the voltage before R6. But now i don't know where to go...also i don't know if this second method i used is the correct one, but it makes more sense to me that the first one wrote down.