Angle at which distance is longest?

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To determine the launch angle for projectile motion when the landing height differs from the launch height, one must consider the vertical displacement in addition to the horizontal distance. The optimal angle for maximum range changes based on the height of the landing position relative to the initial position. For a ball landing on a tower of height h, the angle can be calculated using kinematic equations that incorporate both the initial velocity and the height difference. If aiming for multiple towers, the angle must be adjusted for each specific height to maximize distance. Understanding these principles allows for precise calculations in projectile motion scenarios.
Irrelativity
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I have a question about projectory motion.

I know that if ball is thrown by a person with a initial velocity v(only x and ycomponents), a maximum distance d (distance of x component) can be achived at angle of 45 degree (an angle between the initial velocity and x component of the velocity). But this is only true when the initial position of y component is the same as the terminal position of y conpoment. Here's the my question: how do you guys find the angle at which when the height of a landing position is not the same as the height of the initial position (i.e. Initial y is not equal to terminal y)? Let's say the ball lands on a tower which has a height h with minimum velocity. What's the formula to find the angle?
 
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You mean, what is the angle for the ball to land on the tower? Or to reach maximum range?
Or you have a series of towers and you want to reach the farthest tower possible?
 
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