Angle Calculation for Car-Truck Collision

  • Thread starter Thread starter aszymans
  • Start date Start date
  • Tags Tags
    Angles Car Truck
AI Thread Summary
To calculate the angle of the car-truck combination after their collision, the momentum vectors of both vehicles must be added. The blue car, with a mass of 431 kg moving east at 19 m/s, collides with a purple truck weighing 1298 kg moving south at 12 m/s. After the collision, the two vehicles lock together, requiring the use of the momentum conservation principle to find the resultant vector. The angle can be determined using the arctangent function applied to the ratio of the y-component to the x-component of the resultant momentum. This approach provides the angle south of east for the combined motion post-collision.
aszymans
Messages
11
Reaction score
0
Car Truck Collisins w/ ANGLES!

Homework Statement



A blue car with mass mc = 431 kg is moving east with a speed of vc = 19 m/s and collides with a purple truck with mass mt = 1298 kg that is moving south with a speed of vt = 12 m/s . The two collide and lock together after the collision.



Homework Equations


What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East


The Attempt at a Solution



I have no idea, something to do with adding the vectors. I just don't know how to incorporate the angle
 
Physics news on Phys.org


aszymans said:

Homework Statement



A blue car with mass mc = 431 kg is moving east with a speed of vc = 19 m/s and collides with a purple truck with mass mt = 1298 kg that is moving south with a speed of vt = 12 m/s . The two collide and lock together after the collision.



Homework Equations


What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East


The Attempt at a Solution



I have no idea, something to do with adding the vectors. I just don't know how to incorporate the angle

You will be adding the momentum vectors - so start by using mass and velocity for each vehicle to get the momentum of each.

NOTE: These questions are really frustrating in the masses used [not your fault].
The minimum weight of a Formula 1 racing car [a glorified go-cart] is 640 kg. The idea of having a car of mass 431 kg is fanciful.
A modern Small car has a mass around 1000 kg, and even a small truck will have a mass around 3000 kg.
 


Which principle do you think we usually use in a collision problem?
 


grzz said:
Which principle do you think we usually use in a collision problem?

I'm assuming that was rhetorical. :P

I think you should just find the resultant of the momentum vectors, and then arctan[(y-component)/(x-component)] (components of resultant) should give you the angle.
 


I was encouraging the original poster to a better attemp!
 


Right. Sorry.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top