Angle for n-fold Magnitude Increase of A→ +B→

AI Thread Summary
To determine the angle between two equal magnitude vectors A→ and B→ such that the magnitude of A→ + B→ exceeds that of A→ - B→ by a factor of n, the vectors can be represented in two dimensions. By setting A→ as (1,0) and B→ as (cos(θ), sin(θ)), the resultant for the sum is calculated as 2a cos(θ/2), while for the difference, it is 2a sin(θ/2). The relationship between these two results must satisfy the condition that the sum's magnitude is n times greater than the difference's magnitude. This leads to a mathematical equation that can be solved for θ. Ultimately, the angle θ is crucial for achieving the desired magnitude increase between the vector sums and differences.
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Two vectors A→ and B→ have precisely equal magnitude .For the magnitude of A→ +B→ to be larger than the magnitude of
A→ - B→ by the factor n, what must be the angle between them?
 
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Clearly, 1) the actual length of the vectors doesn't matter, so let's just make them length 1 and 2) since there are only two vectors involved, we can work in two dimensions. So call one vector (1,0) and the other one (cos(theta),sin(theta)). Now just set up your question and solve for theta.
 
The resultant of both constructions are diagonals of a rhombi.

This means that for the sum the resultant will be

2a\cos(\frac{\theta}{2})

where \theta is the require angle and a is the magnitude.

For the difference the angle between the vectors will be 180^o - \theta. In this case the resultant amounts to

2a\sin(\frac{\theta}{2})
 
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