Angular Acceleration during Bowling

AI Thread Summary
A bowler throws a bowling ball down a lane with an initial speed of 6.0 m/s and no initial angular speed. The ball experiences kinetic friction, which causes both linear and angular acceleration, leading to a decrease in speed and an increase in angular speed until it transitions from sliding to smooth rolling. The ball's linear acceleration during sliding is calculated to be -3.33 m/s², and it slides for 0.514 seconds, covering a distance of 2.64 meters. The speed at which smooth rolling begins is determined to be 4.29 m/s. The discussion focuses on applying torque and rotational inertia equations to solve for various aspects of the ball's motion.
Eggyu
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Homework Statement


A bowler throws a bowling ball of radius R = 11 cm down a lane. The ball slides on the lane, with initial speed vcm,0 = 6.0 m/s and initial angular speed 0 = 0. The coefficient of kinetic friction between the ball and the lane is 0.34. The kinetic frictional force fk acting on the ball (Fig. 12-35) causes a linear acceleration of the ball while producing a torque that causes an angular acceleration of the ball. When speed vcm has decreased enough and angular speed has increased enough, the ball stops sliding and then rolls smoothly.


Figure 12-35

(a) What then is vcm in terms of ?
0.11 m·omega
(b) During the sliding, what is the ball's linear acceleration?
-3.33 m/s2
(c) During the sliding, what is the ball's angular acceleration?
_______rad/s2
(d) How long does the ball slide?
0.514 s
(e) How far does the ball slide?
2.64 m
(f) What is the speed of the ball when smooth rolling begins?
4.29 m/s


Homework Equations



Torque = Rotational Inertia * Angular Acceleration

Tangential Velocity = angular velocity * radius



The Attempt at a Solution



I know I need to use the torque equation but the work I've done have not produced anything logical and my work is now just scattered beyond belief. If you need to see the work for any of part of the problem, i can show you that.
 
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For part (c)

I * alpha = r*(friction coefficient)*mg=(2/5)mr^2*alpha

I hope this helps.

Also, can you show how to do parts (d), (e), and (f)?
 
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