Angular acceleration of machinery

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SUMMARY

The discussion focuses on calculating the angular deceleration of a machinery component that decreases its rotation from 760 RPM to 480 RPM over 210 revolutions. The user initially applied the equation ω² = ω₀² + 2αΔθ but encountered issues with unit conversions. The correct approach involves converting RPM to radians per second and the distance traveled in revolutions to radians, leading to a definitive calculation of angular deceleration in rad/s².

PREREQUISITES
  • Understanding of angular motion equations, specifically ω² = ω₀² + 2αΔθ
  • Knowledge of unit conversions between RPM and radians per second
  • Familiarity with angular displacement in radians
  • Basic grasp of angular acceleration and deceleration concepts
NEXT STEPS
  • Learn how to convert RPM to radians per second using the formula: RPM × (2π / 60)
  • Study angular kinematics to understand the relationship between angular velocity, angular acceleration, and angular displacement
  • Practice solving problems involving angular deceleration with varying initial and final velocities
  • Explore the implications of angular deceleration in real-world machinery applications
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in the analysis of rotational dynamics in machinery will benefit from this discussion.

Lance WIlliam
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A piece of machinery is spinning at 760rpm . When a brake is applied, its rotation rate drops to 480rpm while it turns through 210 revolutions.


What is the magnitude of the angular deceleration?

Answer in Rad/s^2

Eqn I used:[tex]\omega[/tex]^2=[tex]\omega[/tex]_0_^2+2[tex]\alpha[/tex](change in theta)

I put 480^2=760^2+2(alpha)210



I got 3.79e-3...
Wrong...:(
what did I do wrong? Ithink its the units, they are very confusing.
 
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i'd convert the distance to radians, and all the speeds to radians per sec right off the bat. so 760 rpm x 2pi / 60 would give you rad/s for example
 
Thankyou
 

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