- #1
Nanabit
- 26
- 0
A rotating wheel requires 2.93 s to complete 37.0 revolutions. Its angular speed at the end of the 2.93 s interval is 97.1 rad/s. What is the constant angular acceleration of the wheel?
I know this should be easy. I'm just missing something. I figured 37 rev = 232 rad (=theta). Then I used the kinematic
Theta(f) = Theta(i)+(omega)(i)t+(1/2)(alpha)(t^2). But somehow it isn't working out. I know the answer should be around 15 or so but I keep getting 120 rad/sec^2!
I know this should be easy. I'm just missing something. I figured 37 rev = 232 rad (=theta). Then I used the kinematic
Theta(f) = Theta(i)+(omega)(i)t+(1/2)(alpha)(t^2). But somehow it isn't working out. I know the answer should be around 15 or so but I keep getting 120 rad/sec^2!