Angular Accelerations of Rigid Bodies with Applied Forces

AI Thread Summary
The discussion focuses on the angular accelerations of three blocks on a frictionless surface when identical forces are applied at different points. There is confusion about whether the accelerations of the blocks' centers of mass will be equal or vary due to potential rotational effects. One participant suggests that the accelerations might differ, with block 3 experiencing the greatest acceleration due to its force application point. However, others clarify that the center of mass accelerations remain equal regardless of the force's application point, emphasizing the importance of distinguishing between linear and angular accelerations. The conversation highlights the need for clarity in interpreting the problem's requirements regarding angular versus linear motion.
KBL-8
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Edit: Tried to post three times and forum kept adding the prompts. Removed Prompts.

Homework Statement


Three blocks are initially at rest on a level frictionless surface. At t=0s, a three identical forces are applied to a different point on each block.
Each block is a rectangle approximately 3x1 oriented with the long sides facing north/south. The center of mass on each block is at (1.5,.5) if the lower left corner of the block is (0,0)

The force on block 1 is applied at about (1,.5)
The force on block 2 is applied at the center of mass
The force on block 3 is applied at about (3,.5)

img233.imageshack.us/img233/959/dynamicsofrigidbodiescq9.png

a) Draw an arrow on the diagram indicating the direction of acceleration of each blocks center of mass. If the acceleration is zero, state so explicitly.
b) Rank the center of mass accelerations from largest to smallest and explain. Draw a point FBD for each block

Homework Equations


Conceptual problem.

The Attempt at a Solution


I think that all the accelerations will be equal. Accelerations are equal at the center of mass regardless of where the force is applied. However I'm confused because it seems like some of the force should go to rotating the object, and if that is true, the accelerations of each of these objects centers of mass will be different.
So either B1=B2=B3 or B2>B1>B3. The FBDs would be different depending on each. If B1=B2=B3, they would be quite simple, just one vector pointing North, but if B2>B1>B3, there would be (I think) the same but with different magnitudes.

It's a pretty simple problem I think, but I may have overthought it and become confused. Help!
Thanks.
 
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I'm going with B3>B1>B2. I'm basing this on the idea that the force has the biggest advantage with B3 because the surface is shouldering half the weight. Regardless of direction, the magnitude would be greater. Maybe?? heh
 
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Welcome to PF!

KBL-8 said:
I think that all the accelerations will be equal. Accelerations are equal at the center of mass regardless of where the force is applied. However I'm confused because it seems like some of the force should go to rotating the object, and if that is true, the accelerations of each of these objects centers of mass will be different.

Hi KBL-8! Welcome to PF! :smile:

You're confused because you're thinking that the rotation of a body might decrease (or increase) its acceleration.

Hint: what is the total acceleration of a body relative to its centre of mass? :smile:
 
Theres an explanation here:

phys150.wikispaces.com/torque+on+blocks
 
KBL-8 said:
… center of mass accelerations …

Hi KBL-8! :smile:

Are you sure the book isn't asking for the angular accelerations?

That would make a lot more sense! :smile:
 
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