Angular and Linear Acceleration on a Wheel

AI Thread Summary
A 68 cm diameter wheel accelerates uniformly from 150 rpm to 270 rpm in 4.1 seconds, resulting in an angular acceleration of 3.1 rad/s². After 1.6 seconds of acceleration, the final angular velocity is calculated to be approximately 20.61 rad/s. The linear velocity at this point is determined to be 7.01 m/s, while the initial velocity was 5.34 m/s. The discussion clarifies that the radial component of linear acceleration sought is indeed the centripetal acceleration, calculated as ω²r. The conversation highlights the importance of understanding the distinction between linear and centripetal acceleration in this context.
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Homework Statement


A 68 cm diameter wheel accelerates uniformly about its center from 150 rpm to 270 rpm in 4.1 s.

1. Determine its angular acceleration. α = 3.1 rad./s^2

2. Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.6 s after it has started accelerating.


Homework Equations



ω final = ω initial + αt
v final = v initial + at
ω * r = v

The Attempt at a Solution



1. (15.7079 rad./s) + (3.0649 rad./s^2)(1.6s)
ω = 20.61174 rad./s

(20.61174 rad./s)(0.34m) = 7.0079916 m/s (final velocity)
(15.7079 rad./s)(0.34m) = 5.340686 m/s (initial velocity)

7.0079916 m/s - 5.340686 m/s / 1.6 s = 1.042066 m/s^2
 
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Hi PeachBanana! :smile:
PeachBanana said:
2. Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.6 s after it has started accelerating.

No, I think they're asking for the centripetal acceleration (ω2r).
 
tiny-tim: Thank you so much. That is much clearer now. The way it was worded was strange.
 
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