(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 5.00-kg ball is dropped from a height of 12.0 m above

one end of a uniform bar that pivots at its center. The bar has mass

8.00 kg and is 4.00 m in length. At the other end of the bar sits

another 5.00-kg ball, unattached to the bar. The dropped ball sticks

to the bar after the collision. How high will the other ball go after

the collision?

2. Relevant equations

L= r X p

L = I [tex]\omega[/tex]

mgh =1/2 mv^2

3. The attempt at a solution

The solution seems to require the conservation of angular momentum. But i am not sure how angular momentum could be conserved? Doesnt the weight of the falling ball provide a net external torque to the system?

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# Homework Help: Angular momentum ball problem

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