Angular Momentum Conservation with a Parakeet Landing on a Turntable

AI Thread Summary
The discussion revolves around the conservation of angular momentum in a scenario involving a parakeet landing on a rotating turntable. The first part of the problem was solved correctly, yielding the final angular speed after the parakeet lands as ωf = Mω1/(M + 2m). In the second part, confusion arose regarding the calculation of angular speed after the parakeet jumps off the turntable. The equations used for conservation of angular momentum were deemed correct, but the final expression for ωf was repeatedly questioned. The participants concluded that while the approach seemed sound, there could be issues with the grading system of the homework platform.
pelmel92
Messages
18
Reaction score
0

Homework Statement



Consider a cylindrical turntable whose mass is M and radius is R, turning with an initial angular speed ω1.

(a) A parakeet of mass m, after hovering in flight above the outer edge of the turntable, gently lands on it and stays in one place on it, as shown below. What is the angular speed of the turntable after the parakeet lands? (Use any variable or symbol stated above as necessary.)
ωf = ? (b) Becoming dizzy, the parakeet jumps off (not flies off) with a velocity relative to the turntable. The direction of is tangent to the edge of the turntable and in the direction of its rotation. What will be the angular speed of the turntable afterwards? Express your answer in terms of the two masses m and M, the radius R, the parakeet speed and the initial angular speed ω1. (Use any variable or symbol stated above along with the following as necessary: v for ||.)
ωf = ?

Homework Equations



L=mvr+Iω
I(turntable)=.5MR^2
I=∑mr^2

The Attempt at a Solution



I had no issues with part one, and correctly found ωf to be equal to Mω1/(M+2m).
But I can't figure out where I've gone wrong with part two...

I thought that, due to the cons. of L, (.5MR^2 +mR^2)ω1= .5MR^2ωf +mvR
but solving for ωf in this equation keeps coming up wrong...

Am I missing something obvious? Any help would be greatly appreciated.
 
Physics news on Phys.org
Your equation looks right to me... what final answer did you end up with?
 
ωf= ω1 + 2mω1/M -2mv/(MR)

do i just suck at algebra?
 
Wow, no that looks good [but I learned that I sure suck at algebra---from my first try... :( ].
Could your solutions be wrong?
 
hold on...thought i caught it but I'm still a bit confused here...

.5MR^2ω1 +mR^2ω1= .5MR^2ωf +mvR
so

.5MR^2ω1 +mR^2ω1 -mvR = .5MR^2ωf

and

(.5MR^2ω1)/(.5MR^2) +(mR^2ω1)/(.5MR^2) - (mvR)/(.5MR^2) = ωf
right?
which means that

ω1 +2(mω1)/M - 2(mv)/(MR) = ωf

maybe I'm just being dense but i can't see where i went wrong...
 
Last edited:
i guess that's always possible... it's a webassign homework, which has been known to fudge the grading on occasion...

but i feel much better about it if you think my approach looked good, thanks for all the help :)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top