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Angular position, speed, and acceleration

  • Thread starter aaronb
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Homework Statement


A dentist's drill starts from rest. After 3.30 s of constant angular acceleration, it turns at a rate of 2.52 multiplied by 104 rev/min.

Find the drill's angular acceleration.

Determine the angle through which the drill rotates during this period

Homework Equations


[tex]\omega[/tex]f=[tex]\omega[/tex]i+[tex]\alpha[/tex]t
[tex]\vartheta[/tex]f=[tex]\varthetai[/tex]+[tex]\omega[/tex]it+(1/2)[tex]\alpha[/tex]t2

The Attempt at a Solution



2.52x10^4=0+[tex]\alpha[/tex]3.3=7636.36
[tex]\vartheta[/tex]f=0+0+1/2=4150

I know the answers are in the wrong units so can someone tell me what to do change my rev/min into rad/s2 for the first part and to find rad for the second part?
 
Last edited:

Answers and Replies

  • #2
LowlyPion
Homework Helper
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  • #3
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Thanks for the link LowlyPion it helped me a lot.
 

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