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Angular position, speed, and acceleration

  1. Apr 24, 2009 #1
    1. The problem statement, all variables and given/known data
    A dentist's drill starts from rest. After 3.30 s of constant angular acceleration, it turns at a rate of 2.52 multiplied by 104 rev/min.

    Find the drill's angular acceleration.

    Determine the angle through which the drill rotates during this period

    2. Relevant equations
    [tex]\omega[/tex]f=[tex]\omega[/tex]i+[tex]\alpha[/tex]t
    [tex]\vartheta[/tex]f=[tex]\varthetai[/tex]+[tex]\omega[/tex]it+(1/2)[tex]\alpha[/tex]t2
    3. The attempt at a solution

    2.52x10^4=0+[tex]\alpha[/tex]3.3=7636.36
    [tex]\vartheta[/tex]f=0+0+1/2=4150

    I know the answers are in the wrong units so can someone tell me what to do change my rev/min into rad/s2 for the first part and to find rad for the second part?
     
    Last edited: Apr 24, 2009
  2. jcsd
  3. Apr 24, 2009 #2

    LowlyPion

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    Homework Helper

  4. Apr 24, 2009 #3
    Thanks for the link LowlyPion it helped me a lot.
     
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