Angular position, speed, and acceleration

[aaronb]

Homework Statement

A dentist's drill starts from rest. After 3.30 s of constant angular acceleration, it turns at a rate of 2.52 multiplied by 104 rev/min.

Find the drill's angular acceleration.

Determine the angle through which the drill rotates during this period

Homework Equations

$$\omega$$_f=$$\omega$$_i+$$\alpha$$t
$$\vartheta$$_f=[tex]\vartheta_i[/tex]+$$\omega$$_it+(1/2)$$\alpha$$t²

The Attempt at a Solution

2.52x10^4=0+$$\alpha$$3.3=7636.36
$$\vartheta$$_f=0+0+1/2=4150

I know the answers are in the wrong units so can someone tell me what to do change my rev/min into rad/s² for the first part and to find rad for the second part?

 

[LowlyPion]

You've found the angular velocity, now all you need to do is find total θ.

Maybe this will help?
http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#rlin

 

[aaronb]

Thanks for the link LowlyPion it helped me a lot.