Angular Speed Homework: Car Brakes, Radii & Revs

AI Thread Summary
A car traveling at 33.8 m/s decelerates at 1.80 m/s² after braking, covering a distance of 317.3 m before stopping. Each tire makes approximately 153.1 revolutions during this distance. When the car has traveled half the total distance, the angular speed of the wheels is calculated to be 23.9 rad/s. The relationship between tangential velocity and angular velocity is established, confirming that the wheels do not skid. The calculations and concepts presented are consistent and accurate.
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Homework Statement


A car initially traveling at 33.8 m/s undergoes a constant negative acceleration of magnitude 1.80 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car does not skid and the tires have radii of 0.330 m? (b) What is the angular speed of the wheels when the car has traveled half the total distance?


Homework Equations


v2 = vo2 + 2aΔx
C=2πr


The Attempt at a Solution


a. Δx = vo2 /-2a
Δx = 33.8 m/s 2 / (-2(-1.80 m/s2))
Δx = 317.3 m

# rev = 317.3 m / 2π (0.33m)
# rev = 153.1

b. v2 = 33.8 m/s2 + 2(-1.80 m/s2)(158.65m)
v = 23.9 m/s --> ω = 23.9 rad/s
 
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Everything is fine except the very last step. The tangential velocity of the wheel is related to the angular velocity via vT = rω. The reason you can assume that v = vT is because the wheels do not skid.
 
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