Angular Velocity in Linear Momentum Equation

StevenJacobs990 · 2016-09-25T03:20:09+00:00

m1v1 = m2v2 v = rω m1(rω)1 = m2(rω)2 m1ω1 = m2ω2 Does this make sense?

Thread starter StevenJacobs990
Start date Sep 24, 2016
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Angular Angular velocity Conservation Linear Linear momentum Momentum Velocity

AI Thread Summary

The discussion focuses on the relationship between angular velocity and linear momentum, specifically through the equations m1v1 = m2v2 and v = rω. Participants explore the application of these equations in the context of Newton's Cradle, where momentum is transferred through colliding balls. The equations m1(rω)1 = m2(rω)2 and m1ω1 = m2ω2 are presented to illustrate this transfer of momentum. The mechanics of the pendulum swinging down and colliding with the balls are highlighted as a practical example. Overall, the equations effectively describe the dynamics of momentum transfer in this scenario.

Sep 24, 2016

StevenJacobs990

m₁v₁ = m₂v₂
v = rω
m₁(rω)₁ = m₂(rω)₂
m₁ω₁ = m₂ω₂
Does this make sense?

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Sep 24, 2016

A.T.

Science Advisor

StevenJacobs990 said:

Does this make sense?

For which scenario?

Sep 24, 2016

StevenJacobs990

A.T. said:

For which scenario?

For Newton's Cradle
because the pendulum in Newton's cradle swings down to collide and transfer momentum to the ball on the other end.

Sep 26, 2016

Khashishi

Science Advisor

Then yes.

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