1. The problem statement, all variables and given/known data For the circuit shown below, the capacitors are initially uncharged. At t=0, the switch S is closed. a) Determine the current in each resistor immediately after the switch is closed. b) Determine the current in each resistor a very long time after the switch is closed. c) Determine the voltage across the capacitor a very long time after the switch is closed. After the switch has been closed for a very long time, it is reopened. d) Determine the initial current I0 through the 100 ohm resistor, as a function of time after the switch is reopened. e) Determine I(t), the current through the 100 ohm resistor, as a function of time after the switch is reopened. f) How long after the switch is reopened does the charge on the capacitor fall to 10% of its fully charged state? 2. Relevant equations V=IR I through a capacitor is I = Cdv/dt = Q/C Kirchoff's Loops Rules 3. The attempt at a solution a) Immediately after the switch is closed, the capacitor behaves ls a short circuit and hence no current flows through the 100 ohm resistor. I in the 200 ohm resistor = V/R=15V/200ohms=.075A b) long after the switch is closed, the capacitor is fully charged and behanves as an open circuit. All of the current passes through both resistors. Left Loop Clockwise: 15V-200ΩI1-100ΩI1=0 Right Loop Counter clockwise: Q/C-100ΩI1-0 I1 is the only current passing through both the resistors I= 20A as for the rest of the parts, I want to make sure I get A and B right before I move on.