[tex]x = cos(t)^7[/tex](adsbygoogle = window.adsbygoogle || []).push({});

[tex]y= 8sin(t)^2[/tex]

Find [tex]\frac{d^2y}{dx^2}[/tex] expressed as a function of [tex]t[/tex]

[tex]\frac{d^2y}{dx^2}[/tex] = _________

well second derivative for y is [tex]\frac{d^2y}{dt} = (16*cos(2t))[/tex]

dx/dt = (-7*cos(t)^6*sin(t))

so dx^2 = ((-7*cos(t)^6*sin(t)))^2 right?

so...[tex]\frac{d^2y}{dx^2}[/tex] = [tex]\frac{(16*cos(2t))}{(-7*cos(t)^6*sin(t))^2} [/tex] right?

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# Homework Help: Another parametric equation

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