- #1
ILoveBaseball
- 30
- 0
[tex]x = cos(t)^7[/tex]
[tex]y= 8sin(t)^2[/tex]
Find [tex]\frac{d^2y}{dx^2}[/tex] expressed as a function of [tex]t[/tex]
[tex]\frac{d^2y}{dx^2}[/tex] = _________
well second derivative for y is [tex]\frac{d^2y}{dt} = (16*cos(2t))[/tex]
dx/dt = (-7*cos(t)^6*sin(t))
so dx^2 = ((-7*cos(t)^6*sin(t)))^2 right?
so...[tex]\frac{d^2y}{dx^2}[/tex] = [tex]\frac{(16*cos(2t))}{(-7*cos(t)^6*sin(t))^2} [/tex] right?
[tex]y= 8sin(t)^2[/tex]
Find [tex]\frac{d^2y}{dx^2}[/tex] expressed as a function of [tex]t[/tex]
[tex]\frac{d^2y}{dx^2}[/tex] = _________
well second derivative for y is [tex]\frac{d^2y}{dt} = (16*cos(2t))[/tex]
dx/dt = (-7*cos(t)^6*sin(t))
so dx^2 = ((-7*cos(t)^6*sin(t)))^2 right?
so...[tex]\frac{d^2y}{dx^2}[/tex] = [tex]\frac{(16*cos(2t))}{(-7*cos(t)^6*sin(t))^2} [/tex] right?