Another problem that I guessed right.

  • Thread starter Thread starter AznBoi
  • Start date Start date
AI Thread Summary
The discussion revolves around solving the equations 2|x| + 3 = 4 and |y|/3 + 1 = 2 to determine possible values for |x| + |y|. The correct answer to the question posed is D (10), as it is not divisible by 2 or 4, unlike the other options. Participants suggest solving for x and y by considering multiple combinations due to the absolute values. There is also a suggestion to consolidate questions into a single thread for efficiency. The original poster confirms they found a solution.
AznBoi
Messages
470
Reaction score
0
-_- I'm getting annoyed and I suppose that you guys are too of problems that I don't know exactly how it works! I've made educated guesses and apparently have guessed this one right.

Here goes:
If 2lx+3l=4 and ly+1l/3=2, then lx+yl could equal each of the following EXCEPT:

a) 0
b) 4
c) 8
d) 10
e) 12
 
Mathematics news on Phys.org
Oops, the correct answer is D and I think this is because the other numbers are divisble by 4 and 2 except 10?? lol Can anyone tell me a way of solving this numerically? Plug in numbers? solve for x and y? Please also state the way you think is most efficient. Thanks!
 
Solve for x in both expressions. Since you have an absolute, there is 2 solutions to each expression. There is a total of 4 combinations for x + y, find all of them and deduce which answer is wrong. And by the way, why don't you make a thread where you can post all your questions? No need to make 3 threads. :-p
 
Last edited:
haha ok, yeah I solved it thanks!
 
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top