Another roller coaster question

AI Thread Summary
The discussion revolves around calculating the forces acting on a roller coaster at the top and bottom of a loop. The forces are represented by the equations mg - mv²/r for minimum weight and mg + mv²/r for maximum weight. Participants share their attempts at solving for mass and acceleration, with one user calculating the mass to be 60 kg using the combined forces at the top and bottom. The consensus is that constructing equations and manipulating them yields a clearer solution for determining mass without needing to find the period or velocity. The final calculation confirms the mass as 60 kg, demonstrating the effectiveness of the approach.
vorcil
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http://img13.imageshack.us/img13/9297/masteringphysicsq1.jpg

At the bottom it's 510N, Top 666N,

at bottom Fnormal=netforce= mv^2/r + mg

http://img13.imageshack.us/img13/8244/masteringphysicsq1g.jpg
-my attempt

I'm not sure how to figure out the acceleration
or determine the time for one loop on the graph.
 
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great 510 n = 5 seconds...
666n = 15 seconds
 
I don't think you need to determine the period or the velocity.

Where will the weight be the minimum? And the maximum?

Presuming that the ferris wheel is not a super spinning Whirl-a-Gig, then you know

mg - mv2/r = Min
mg + mv2/r = Max

Then just solve for m*g.
 
LowlyPion said:
I don't think you need to determine the period or the velocity.

Where will the weight be the minimum? And the maximum?

Presuming that the ferris wheel is not a super spinning Whirl-a-Gig, then you know

mg - mv2/r = Min
mg + mv2/r = Max

Then just solve for m*g.

I got two different awnsers, for the coaster at the bottom 12.171kg and top 14.52kg
i think I've done it wrong :\
 
vorcil said:
I got two different awnsers, for the coaster at the bottom 12.171kg and top 14.52kg
i think I've done it wrong :\

Try constructing the equations.

Then subtract 1 from the other.

You will determine then what mv2/r is and then you can figure the weight from either of the 2 equations.

I only get 1 answer.
 
LowlyPion said:
Try constructing the equations.

Then subtract 1 from the other.

You will determine then what mv2/r is and then you can figure the weight from either of the 2 equations.

I only get 1 answer.

What like?
666-510 = (mg + mv^2/r) - (mg - mv^2/r)
i can't figure out the velocity for the mv^2/r
 
666 = mg + mv^2/r
510 = mg - mv^2/r

666+510 = 2mg + - mv^2/4
= 1176 = 2mg
1176/9.8 = 120
120/2 = 60

60kg?
 
vorcil said:
666 = mg + mv^2/r
510 = mg - mv^2/r

666+510 = 2mg + - mv^2/4
= 1176 = 2mg
1176/9.8 = 120
120/2 = 60

60kg?

That's right. Adding them works too. In fact better as it yields the m*g directly.

m = 1176/(2*9.8) = 60
 
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