Antiderivative of Sin^3(x)Cos^4(x): Solutions & Examples

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Homework Help Overview

The problem involves computing the antiderivative of the function \(\int (sin^3(x))(cos^4(x)) dx\), which falls under the subject area of calculus, specifically integration techniques involving trigonometric functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster expresses difficulty in applying integration by parts and seeks guidance on managing the problem. Some participants suggest a standard method for handling odd powers of trigonometric functions, while others propose a substitution involving \(u = cos(x)\). There is a discussion about the implications of the substitution and the resulting expression.

Discussion Status

The discussion is ongoing, with various approaches being explored. Some participants have provided insights into potential substitutions and transformations, while others are clarifying the implications of these methods. There is no explicit consensus on the best approach yet.

Contextual Notes

Participants are navigating the complexities of trigonometric identities and substitutions, with some uncertainty about the correct application of integration techniques. The original poster's struggle with the problem setup is evident, and assumptions about the methods to be used are being questioned.

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Homework Statement


Compute the following antiderivative [tex]\int (sin^3(x))(cos^4(x)) dx[/tex]


Homework Equations





The Attempt at a Solution


If this problem requires use of integration by parts I'm struggling to work out to split it up and make it manageable. Have searched countlessly for a similar example on the net but have had no luck. Thanks
 
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There is a standard "method" when you have a trig function to an odd power.

Since sin(x) it to the 3rd power, take one out to use with dx, convert sin2(x) to cos:
[tex]\int sin^3(x)cos^4(x)dx= \int sin^2(x)cos^4(x) sin(x)dx= \int (1- cos^2(x))cos^4(x) sin(x)dx[/itex]<br /> Now what substitution will make that easy?[/tex]
 
All you should do is new variable u = cos(x). You'll get integral u^4-u^6.
 
Actually, [tex]u^6 - u^4[/tex] due to the negative in the derivative of [tex]cos(x)[/tex]
 
Last edited:
fikus what do you mean, i can do a substitution straight away?
 
tunabeast said:
fikus what do you mean, i can do a substitution straight away?
you can once you find that the derivative of your substitution appears in your original problem
 
tunabeast said:
fikus what do you mean, i can do a substitution straight away?
I believe that is what everyone as been trying to tell you!
 

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