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Any help will be appreciated assuming a pretty easy integral

  1. Jan 17, 2012 #1
    Any help will be appreciated...assuming a pretty easy integral....

    ∫f(t) dt = 9 [0, 1]

    Find:

    ∫f(10t)dt [0, 0.1]
    ∫f(1 - 10t)dt [0, 0.1]

    Any idea on how to get started with this one?
     
  2. jcsd
  3. Jan 17, 2012 #2

    Dick

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    Re: Any help will be appreciated...assuming a pretty easy integral....

    Change variables with a u-substitution. For the first one try u=10t. What is du?
     
  4. Jan 17, 2012 #3
    Re: Any help will be appreciated...assuming a pretty easy integral....

    10dt!
     
  5. Jan 17, 2012 #4

    Dick

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    Re: Any help will be appreciated...assuming a pretty easy integral....

    Ok, so change the t integral to a u integral.
     
  6. Jan 17, 2012 #5
    Re: Any help will be appreciated...assuming a pretty easy integral....

    1/10∫f(u)du ?
     
  7. Jan 17, 2012 #6

    Dick

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    Re: Any help will be appreciated...assuming a pretty easy integral....

    Looks good so far. And what are the u limits? The t limits were [0,0.1].
     
  8. Jan 17, 2012 #7
    Re: Any help will be appreciated...assuming a pretty easy integral....

    From 0 to 0.1.

    Does ∫f(u)du = 9?
     
  9. Jan 17, 2012 #8

    Dick

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    Re: Any help will be appreciated...assuming a pretty easy integral....

    It won't be 9, if the u limits are 0 to 0.1. But they aren't. If t=0.1, what's the corresponding u?
     
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