# Anyone knows how to solve a cryptogram?

1. Feb 19, 2012

### Crazysah

1. The problem statement, all variables and given/known data

2. Relevant equations

Use whatever tools you wish (though we recommend the frequency-analysis and monoalphabetic substitution-cipher tools, some serious elbow grease and some ingenuity) to uncover the plaintext.
That is the cryptogram without any spaces for punctuation.

3. The attempt at a solution

Now I've tried to use frequency counting and a mono-alphabetic substitution cipher with no luck.

Anybody have any idea on this one?

Thanks,
Crazysah

2. Feb 19, 2012

### Staff: Mentor

is this for a course?

The suggestion of using frequency analysis and monalphabetic subs tools means its probably a monoaphabetic substitution cipher. If you can identify the first few letters via the freq analysis then you might find they used a keyword to construct the cipher. As an example: dumbwaiter where d=a / u=b / m=c / b=d... followed by the remaining letters in order that aren't in dumbwaiter.

3. Feb 19, 2012

### Crazysah

Yes. He says it is something we haven't done in class before and we have done monoalphabetic substitution ciphers before. Also, I already tried using a keyword but I'm just not getting the right keyword. I tried identifying the first few letters to form a word but no luck.

4. Feb 19, 2012

### jhae2.718

Do you have ideas on what the cipher may be? From frequency analysis you can get a feel for what you are dealing with. (e.g. a flatter frequency distribution may be a polyalphabetic substitution cipher.)

5. Feb 19, 2012

### Crazysah

No. I do not know what the cipher may be but I'm thinking it may be closest to a monoalphabetic substitution cipher.
Also, some letters may repeat itself. I think that might be the trick.
Just to say it again: Spaces and punctuation have been removed

6. Feb 20, 2012

### Redbelly98

Staff Emeritus

If you have done the frequency count, why not post the results of it? It seems that would increase the chances that somebody could help you out.